/**
 * @description: 输入需要排序的两个参数，返回index，配合sort函数使用
 * @param {Date | milliseconds} 必选
 * @return: {Date} 返回0时0分0秒的Date
 */
export function getChartType (char) {
  // 数字可按照排序的要求进行自定义，我这边产品的要求是
  // 数字（0->9）->大写字母（A->Z）->小写字母（a->z）->中文拼音（a->z）
  if (/^[\u4e00-\u9fa5]$/.test(char)) {
    return ['zh', 300]
  }
  if (/^[a-zA-Z]$/.test(char)) {
    return ['en', 200]
  }
  if (/^[0-9]$/.test(char)) {
    return ['number', 100]
  }
  return ['others', 999]
}

export function sortDevName (str1, str2) { // 混合排序
  let res = 0
  for (let i = 0; ;i += 1) {
    if (!str1[i] || !str2[i]) {
      res = str1.length - str2.length
      break
    }
    const char1 = str1[i]
    const char1Type = getChartType(char1)
    const char2 = str2[i]
    const char2Type = getChartType(char2) // 类型相同的逐个比较字符
    if (char1Type[0] === char2Type[0]) {
      if (char1 === char2) {
        break
      }
      if (char1Type[0] === 'zh') {
        res = char1.localeCompare(char2)
      } else if (char1Type[0] === 'en') {
        res = char1.charCodeAt(0) - char2.charCodeAt(0)
      } else {
        res = char1 - char2
      }
      break
    } else { // 类型不同的，直接用返回的数字相减
      res = char1Type[1] - char2Type[1]
      break
    }
  }
  return res
}

/**
 * @description: 输入一个数组，'版本号'
 * @param {Array} 必选
 * @return: {Array} 返回排序后的数组
 */
export function sortVersion (arr, Isreverse = false) {
  let newList = arr.sort((a, b) => {
      let i = 0
      const arr1 = a.split('.')
      const arr2 = b.split('.')

      while (true) {
          const s1 = arr1[i]
          const s2 = arr2[i++]

          if (s1 === undefined || s2 === undefined) {
              return arr2.length - arr1.length
          }

          if (s1 === s2) continue

          return s2 - s1
      }
  })
  return newList
}

/**
 * @description: 输入一个'版本号'
 * @param {String} 必选
 * @return: {String} 返回版本号的下一个版本
 */
export function supgradeVersion (str) {
  let newstr = ''
  let arr = str.split('.').map(ele => Number(ele)).reverse()
  arr.forEach((ele, index) => {
    switch (index) {
      case 0:
        if (ele === 9) {
          arr[index] = 0
          arr[index + 1] = arr[index + 1] + 1
        } else {
          arr[index] = ele + 1
        }
        break
      case arr.length:
        arr[index] = ele + 1
        break
      default:
        if (ele > 9) {
          arr[index] = 0
          arr[index + 1] = arr[index + 1] + 1
        } else {
          arr[index] = ele
        }
        break
    }
  })
  newstr = arr.reverse().join('.')
  return newstr
}