114 lines
2.8 KiB
JavaScript
114 lines
2.8 KiB
JavaScript
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/**
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* @description: 输入需要排序的两个参数，返回index，配合sort函数使用
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* @param {Date | milliseconds} 必选
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* @return: {Date} 返回0时0分0秒的Date
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*/
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export function getChartType (char) {
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// 数字可按照排序的要求进行自定义，我这边产品的要求是
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// 数字（0->9）->大写字母（A->Z）->小写字母（a->z）->中文拼音（a->z）
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if (/^[\u4e00-\u9fa5]$/.test(char)) {
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return ['zh', 300]
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}
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if (/^[a-zA-Z]$/.test(char)) {
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return ['en', 200]
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}
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if (/^[0-9]$/.test(char)) {
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return ['number', 100]
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}
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return ['others', 999]
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}
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export function sortDevName (str1, str2) { // 混合排序
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let res = 0
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for (let i = 0; ;i += 1) {
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if (!str1[i] || !str2[i]) {
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res = str1.length - str2.length
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break
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}
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const char1 = str1[i]
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const char1Type = getChartType(char1)
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const char2 = str2[i]
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const char2Type = getChartType(char2) // 类型相同的逐个比较字符
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if (char1Type[0] === char2Type[0]) {
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if (char1 === char2) {
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break
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}
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if (char1Type[0] === 'zh') {
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res = char1.localeCompare(char2)
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} else if (char1Type[0] === 'en') {
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res = char1.charCodeAt(0) - char2.charCodeAt(0)
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} else {
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res = char1 - char2
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}
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break
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} else { // 类型不同的，直接用返回的数字相减
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res = char1Type[1] - char2Type[1]
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break
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}
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}
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return res
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}
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/**
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* @description: 输入一个数组，'版本号'
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* @param {Array} 必选
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* @return: {Array} 返回排序后的数组
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*/
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export function sortVersion (arr, Isreverse = false) {
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let newList = arr.sort((a, b) => {
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let i = 0
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const arr1 = a.split('.')
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const arr2 = b.split('.')
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while (true) {
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const s1 = arr1[i]
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const s2 = arr2[i++]
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if (s1 === undefined || s2 === undefined) {
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return arr2.length - arr1.length
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}
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if (s1 === s2) continue
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return s2 - s1
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}
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})
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return newList
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}
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/**
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* @description: 输入一个'版本号'
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* @param {String} 必选
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* @return: {String} 返回版本号的下一个版本
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*/
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export function supgradeVersion (str) {
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let newstr = ''
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let arr = str.split('.').map(ele => Number(ele)).reverse()
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arr.forEach((ele, index) => {
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switch (index) {
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case 0:
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if (ele === 9) {
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arr[index] = 0
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arr[index + 1] = arr[index + 1] + 1
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} else {
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arr[index] = ele + 1
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}
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break
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case arr.length:
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arr[index] = ele + 1
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break
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default:
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if (ele > 9) {
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arr[index] = 0
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arr[index + 1] = arr[index + 1] + 1
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} else {
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arr[index] = ele
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}
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break
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}
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})
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newstr = arr.reverse().join('.')
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return newstr
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}
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